2x^2-3xy+3y^2=50

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Solution for 2x^2-3xy+3y^2=50 equation: 


Simplifying
2x2 + -3xy + 3y2 = 50

Reorder the terms:
-3xy + 2x2 + 3y2 = 50

Solving
-3xy + 2x2 + 3y2 = 50

Solving for variable 'x'.

Reorder the terms:
-50 + -3xy + 2x2 + 3y2 = 50 + -50

Combine like terms: 50 + -50 = 0
-50 + -3xy + 2x2 + 3y2 = 0

The solution to this equation could not be determined.

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